Question

2) A cricket ball.of mass 70g moving with a velocity of 0.5 m/s is stopped by a player in 0.255.
What is the force applied by the player to stop the ball?​

Answer 1

Answer:

Given:

mass of  ball =m=70g=0.070kg

Initial velocity=u= 0.5 m/s

Final velocity =v=0m/s

time=t= 0.5 sec

a= v-u/t

⇒0-0.5/0.5

⇒-1 m/s²

F=m*a

⇒0.07x-1

⇒-0.07 N

hope it helps uh...

Explanation:

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