Question

2. A cube of length p cm is mounted on a cuboid of length 3p×p×p then find its total surface area.​

Answer 1

Answer:

12p

Step-by-step explanation:

so u add the four sides

Answer 2

Answer:

18$p^{2}$

Step-by-step explanation:

Suraface area of cube= 6(lenght x width)

=6(p x p)

=6($p^{2}$)

Cube=6$p^{2}$

Surface area of cuboid=2(length x width)+2(width x height)+2(lenght x height)

=2(3p x p)+2(p x p)+2(3p x p)

=2(3$p^{2}$)+2($p^{2}$)+2(3$p^{2}$)

=6$p^{2}$+2$p^{2}$+6$p^{2}$

=14$p^{2}$

Because the cube is on top of the cuboid we have tpo minus the area of the cube face that is on the bottom and part of the cuboid top face.

So: actual cube surface area=5$p^{2}$

Top cuboid face area: 3$p^{2}$-$p^{2}$=2$p^{2}$

Whole cuboid surface area is: 13$p^{2}$

Therfore total surface are of the whole shape=

13$p^{2}$+5$p^{2}$

=18$p^{2}$