Question

2. A cuboidal oil tin is of dimensions 30 cm x 40 cm x 50 cm. Find the cost of tin required for making
20 such tins if the cost of tin sheet is 20 per m
THI
hreadth is 5 m and height is 4 m.​

Answer 1

Answer:

30×40×50=60000.

60000/20=3000.

Answer 2

Original question

$\:\:$

A cuboidal oil tin is 30 cm by 40 cm by 50 cm. Find the cost of the 20 such tins if the cost of tin sheet is Rs 20 per square metre.

$\:\:$

$\huge{\blue{\bold{\underline{\underline{Answer :}}}}}$

$\:\:$

$\large\underline{\green{\bf Given :-}}$

$\:\:$

• A cuboidal oil tin is 30 cm by 40 cm by 50 cm

$\:\:$

• Cost of tin sheet is Rs 20 per square metre

$\:\:$

$\large\underline{\red{\bf To \: Find :-}}$

$\:\:$

• The cost of the 20 such tins

$\:\:$

$\large\underline{\orange{\bf Solution :-}}$

$\:\:$

$\underline{\bold{\texttt{Total surface area of cuboid :}}}$

$\:\:$

➠ 2(lb + bh + lh) ⚊⚊⚊⚊ ⓵

$\:\:$

Where ,

$\:\:$

• l = Length

• b = Breadth

• h = Height

$\:\:$

$\underline{\bold{\texttt{Total surface area of given oil tin :}}}$

$\:\:$

• l = 30 cm

• b = 40 cm

• h = 50 cm

$\:\:$

⟮ Putting these values in⓵ ⟯

$\:\:$

➜ 2(lb + bh + lh)

$\:\:$

➜ 2(30 × 40 + 40 × 50 + 30 × 50)

$\:\:$

➜ 2(1200 + 2000 + 1500)

$\:\:$

➜ 2(4700)

$\:\:$

➨ 9400 sq.cm.

$\:\:$

$\underline{\bold{\texttt{Converting sq. cm. to sq. m. :}}}$

$\:\:$

➜ $\sf \dfrac { 9400 } { 100 × 100 }$

$\:\:$

➜ 0.94 sq. m.

$\:\:$

• Hence the total surface area of 1 oil tin is 0.94 sq. m.

$\:\:$

$\underline{\bold{\texttt{Total surface area of 20 oil tin :}}}$

$\:\:$

➜ 0.94 × 20

$\:\:$

➜ 18.8 sq. m.

$\:\:$

• Hence the area of 20 oil tin is 18.8 sq. m.

$\:\:$

$\underline{\bold{\texttt{Cost of tin required to make 20 oil tin :}}}$

$\:\:$

➜ 18.8 × 20

$\:\:$

➨ Rs 376

$\:\:$

• Hence the cost of the 20 such tins is Rs 376

$\:\:$

═════════════════════════