2. A current of 5.0 A is flowing upward in a long
vertical wire placed in a uniform horizontal
northward magnetic field of 0.02 T. How much
force and in what direction will the field exert on
0.06 m length of the wire ?
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Answer:
2. A current of 5.0 A is flowing upward in a long
vertical wire placed in a uniform horizontal
northward magnetic field of 0.02 T. How much
force and in what direction will the field exert on
0.06 m length of the wire ?
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Answer:6×10^-3 N
Explanation: Given,
I= 5.0 A
B= .02
L=.06m
•.• we know
F= ILBsin90° [sin90=1 (northward magnetic)
= 5 ×.06×.02×1
= 6×10^-3N
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