Question

2. A farmer moves along the
boundary of a square field of side
10 min 40 s. What will be the
magnitude of displacement of the
farmer at the end of 2 minutes 20
seconds from his initial position?​

Answer 1

C...... square side = 10m///

so perimeter = 40cm

and in 40s the person covers this distance.... so....

speed = 1m/s

now in 2min 20s =120s +20s =140 s

so.... distance covered = speed x time =140s x 1m/s = 140m

140 meters....

cheers:)