Question

2. A farmer moves along the
boundary of a square field of side
10 m in 40 s. What will be the
magnitude of displacement of the
farmer at the end of 2 minutes 20
seconds from his initial position?​

Answer 1

Answer:

10$\sqrt{2\\}$

Explanation:

2 min 20s = 140 s = 40*3 + 20

therefore in 20 s he will reach the other end of the diagonal

there displacement = lenght of diagonal = 10root2