Question

2. A farmer moves along the
boundary of a square field of side
your
10 min 40 s. What will be the
magnitude of displacement of the
farmer at the end of 2 minutes 20
seconds from his initial position?
​

Answer 1

Answer:

Farmer takes 40 s to move along the boundary. Thus, after 3.5 round farmer will at point C of the field. Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.

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Answer 2

Explanation:

Answers

deepsen640

deepsen640

Answer:

Displacement of the farmer in 2 minutes and 20 seconds = 10√2 meters

Step by step explanations :

given that,

A farmer moves along the boundary of a square field of side 10 m in 40 s

here,

side of the square feild = 10 m

so,

its boundary length = its perimeter

perimeter of the square = 4 × side

= 4 × 10 = 40 m

so,

perimeter of the square = 40 m

According to the question,

Farmer moves 40 meter in 40 seconds

given that,

farmer continued moving on the boundary of the square field

for 2 minutes 20 seconds

120 + 20

= 140 seconds

now,

number of revolution of square field

140 = 40 + 40 + 40 + 20

so,

here is 3 complete revolution

and 20 m extra

and

in, 20 meter he will go one corner to the another

so,

displacement = diagonal of the square field

diagonal of square = √2 a

where,

a is the side of the square

so,

length of diagonal = 10√2 m

so,

Displacement of the farmer in 2 minutes and 20 seconds

= 10√2 meters

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