Question

2. A farmer moves along the
boundary of a square field of side
10 min 40 s. What will be the
magnitude of displacement of the
farmer at the end of 2 minutes 20
seconds from his initial position?​

Answer 1

Answer:

hello here is your answer mate

Total distance covered 10m in 40sec

Total time taken= 2min 20sec= 140sec

Total round completed = 140/40=3.5 rounds

So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.

AC2= AB2 +BC2

AC2= (10)2 +(10)2

AC2= 100+100

AC2=200

AC = (200)1/2

AC= 10× (2) ½

Explanation:

hope it helped you friend if it helps you mark it as brainliest

Answer 2

Explanation:

Explanation:Farmer takes 40 s to move along the boundary. ... Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.