Question

2. A farmer moves along the
boundary of a square field of side
10 m in 40 s. What will be the
magnitude of displacement of the
farmer at the end of 2 minutes 20
seconds from his initial position?​

Answer 1

Answer:

Side of the square field = 10 m.

Time taken = 40 seconds.

Total time = 2 x 60 + 20 = 140 seconds.

Total rounds = Total distance / Distance in 1 round

140/40 = 3.5 rounds.

Displacement = shortest distance. Hence it'd be in the hypotenuse.

By Pythogorean Theorem,

displacement =

$\sqrt{ {10}^{2} + {10}^{2} }$

$\sqrt{200}$

$10 \sqrt{2}$

Ans = 10√2 m.