2. A farmer moves along the boundary of a square field of side 10m in 40s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
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Answer:
answer is 14.1 means his initial position is 14.1
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Explanation:
Let ABCD be a square field of side 10 m Revolution time of farmer along the boundary of the field,
T = 40 s
Time of walk, t = 2 min 20 s = 140 s
A Number of revolutions completed by the farmer,
140 = 40 = 3 1
It means that starting from point A, the farmer will complete three full rounds of his field and then completing
revolution reaches to point C.
Magnitude of displacement of the farmer = straight distance from initial position to final position =
= AC = (AB + (BC?
=
(10)2 + (10) = 200 = 10-/2 m 14.1 m
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