Math, asked by Vani8lijjaramy0joe, 1 year ago

2.A father is 30 years older than his son . in 12 years .the man will be three times as old as his son . find their present age .

Answers

Answered by Golda
744
Solution:-
Let the present age of the son be 'x' years.
Then father's age will be (x + 30) years
Given : After 12 years, the father will be three times as old as his son. Therefore, 
(x + 12)3 = x + 30 + 12
3x + 36 = x + 42
3x - x = 42 - 36
2x = 6
x = 3 
The present age of son is 3 years and the present age of the father is 3 + 30 = 33 years.
Answer.
Answered by Anonymous
223
Hey !!! ^_^

Here is your answer

⬇️⬇️⬇️⬇️⬇️⬇️⬇️

Let the present age of son be 'x' yrs and father age be (x + 30) yrs

After 12 yrs the age of father will be 3 times as old as his son ..

Age of Son

3(x + 12) yrs

Age of father

x + 30 + 12 = (x + 42) yrs ..

A/Q

3x + 36 =.x + 42

3x - x = 42 - 36

2x = 6

x = 3

________________________

The present age of son be

&lt;b&gt; 3 yrs.............<br /><br />The present age of father <br />3 + 30 <br /><br />=&lt;b&gt;33 yrs <br /><br />====================================<br /><br />i hope it will help you

Thank you

☺️
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