Question

2. A father is twice as old as his son. 20 years
ago the age of the father was 12 times the
age of the son. The present age of the father
is:​

Answer 1

Answer:

Hope it will help you...... .

Answer 2

Step-by-step explanation:

Let Son Present age be x years.

Then, Father age = 2x

20 years ago,

Son age = ( Present age - 20 ) years

= ( x - 20 ) years

Father age = ( Present age - 20 ) years

= ( 2x - 20 ) years

Given,

Father age = 12 time the age of the son

➠ 2x - 20 = 12 ( x - 20 )

➠ 2x - 20 = 12x - 240

➠ 2x - 12x = -240 + 20

➠ - 10x = -220

➠ x = 22

Therefore,

Son age is 22 years and father age = 2× 22 = 44 years