Question

2. A field is 70 m long and 40m broad. In one corner of the field, a pit which is 10 m
long, 8m broad and 5m deep, has been dug out. The earth taken out of it is evenly
spread over the remaining part of the field. Find the rise in the level of the field.

Answer 1

• Given

• Dimensions of the field -
• Length of the field = 70 m
• Breadth of the field = 40 m
• In one corner of the field a pit is dug whose dimensions are -
• Length of the pit = 10 m
• Breadth of the pit = 8 m
• Height of the pit = 5 m

• To find

• Rise in the level of the field

• Solution

Area of the rectangular field = length × breadth

⟶ 70 × 40

⟶ 2800 m²

• Area of the rectangular field = 2800 m²

Area of the pit = length × breadth

⟶ 10 × 8

⟶ 80 m²

• Area of the pit = 80 m²

Area of the remaining field = (2800 - 80) m² = 2720 m²

• The area of the earth taken out = 2720 m²

• Rise in the level of the field = Volume of the pit/Area of the earth taken out

Volume of the pit = length × breadth × height

⟶ 10 × 8 × 5

⟶ 400 m³

• Volume of the pit = 400 m³

⟶ 400/2720

⟶ 0.147 m or 14.7 cm

Answer 2

☆Answer☆

Given:-

• A rectangular field 70 m long and 40 m broad.
• A pit of length 10m breadth of 8 m and height is 5 m

To Find:-

• Rise in the level of field if the earth taken out of it is evenly spread over the remaining part of the field.

Solution:-

Area of rectangular field = length × breadth

=> (70×40) m²

=> 2800 m²

Area of pit = length × breadth

=> (10×8) m²

=> 80 m²

• Area of remaining field

=> (2800-80) m²

=> 2720 m²

We have,

Rise in the level of field

= Volume of pit/Area of earth takes out

=> (10×8×5)/2720

=> 400/2720

=> 0.147 m²

In CMs

=> 14.7 cm²

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