Question

(2)(a) Find the distance between the points(2,3) and(3.-1).
(b) Does the lines joining the points(2.3) and(3,-1)
Passes through the point(5.9)? Justify your answer. (4)​

Answer 1

Answer:

The equation of any straight line can be written as y=mx+c, where m

is its slope and c is its y - intercept.

Slope of the line passing through points (x

1

,y

1

) and (x

2

,y

2

) =

x

2

−x

1

y

2

−y

1

So, slope of the line joining (−5,6),(−6,5)=

5−6

−6+5

=1

Slope of the line perpendicular to this line =−1

So, equation of the required line will be y=−x+c

Since, this line passes through (2,3), on substituting (2,3) in the equation we get

3=−2+c

=>c=5

Hence, required equation of the line is y=−x+5 or x+y−5=0

Answer 2

Answer:

√17

Step-by-step explanation:

(a)√(3-2)²+(-1-3)²

=√1+16

=√17