2. A floral design on the floor of a building consists of 2800 tiles. Each tile is in the shape of a parallelogram of altitude 10 cm and base 14 cm. Find the area of the floor covered by the floral design and the cost of -polishing it at the rate of 75 per m².
Answers
Step-by-step explanation:
Showing results for 2. A floral design on the floor of a building consists of 2800 tiles. Each tile is in the shape of a parallelogram of altitude 10 cm and base 14 cm. Find the area of the floor covered by the floral design and the cost of "-polishing" it at the rate of 75 per m².
Search instead for 2. A floral design on the floor of a building consists of 2800 tiles.
Each tile is in the shape of a parallelogram of altitude 10 cm and base 14 cm. Find the area of the floor covered by the floral design and the cost of -polishing it at the rate of 75 per m².
Answer:
Area of the floor covered by floral design is 39.2 sq. m. and cost of polishing it is Rs.2940
Step-by-step explanation:
Given:
No. of tiles used on the floor = 2800
Altitude of parallelogram = 10 cm.
Base of parallelogram = 14 cm.
Area of 1 tile = area of parallelogram (as tiles are in the shape of a parallelogram.)
Area of parallelogram = base × height
= 14 × 10 = 140 sq.cm.
Area of the floor = area of 1 tile × no. of tiles
= 140 × 2800 =392000 sq.cm.
1 sq.cm. = 1/10000 sq.m.
392000 sq.cm.= 392000 /10000 sq.m. =39.2 sq.m.
Cost of polishing of 1 sq.m. = Rs.75
Cost of polishing 39.2 sq.m. =75 ×39.2 = Rs.2940