Question

2) A football player kicked a ball at an angle of 37o above the horizontal with an initial velocity of 20 m/s, what is the maximum height reached by the ball?

Answer 1

Answer:

Angle of projection θ=30

0

initial velocity, μ=15 m/sec

a) Maximum height =

2g

μ

2

sin

2

θ

=

2×9.8

(15)

2

×sin

2

30

0

=2.869 m

Explanation:

i hope this answer is right