Math, asked by prachi1753, 5 months ago

2. A garrison of 120 men has provision for 30 days. At the end of five days, five more
men joined them. How many days can they sustain on the remaining provision?​

Answers

Answered by pratyakshjoshi
1

Step-by-step explanation:

Let after the joining of 5 men (after 5 days), It took x days to sustain on the remaining provision then,

According to the question-

120×30=120×5+125×x

(120×30)−(120×5)=125x

120(30−5)=125x

120×25=125x

120=5x

x=24 days

Hence, this is the required answer.

Answered by Anonymous
2

Answer:

Given that,

Number of men = 120

Time = 30 days

At the end of 5 days, 5 more men joined them.

For 120 men there is provision for 30 days

If 1 man needs 1 unit of provision in a day

Then, total provision = 120\times30120×30

Total provision =3600

120 men in 5 days will take = 120\times5120×5

120 men in 5 days will take = 600 unit of provision

Remaining provision = 3600-600

Remaining provision =3000 units

5 more men joined and now there are total 125 men

We need to calculate the days on the remaining provision

1 day provision requirement for 125 men = 125 units

Days for which they can sustain on remaining provision =

\dfrac{3000}{125}

125

3000

Days for which they can sustain on remaining provision =24 days

Hence, They can sustain on remaining provision for 24 days.

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