Question

2. A hammer of mass 300g, moving of 75m/s strikes a nail. The nail stops in a
very short time of 3 x 10 seconds. What is the change in momentum and
the force exerted by nail on hammer?​

Answer 1

Question :-

• A hammer of mass 300g, moving of 75m/s strikes a nail. The nail stops in a very short time of 3 x 10 seconds. What is the change in momentum and the force exerted by nail on hammer?

AnSwer:-

• Force exerted by the nail is 2250N.

Given:-

• Mass = 300g = 0.3 kg
• V = 0 m/s
• U = 75 m/s
• T = 3 x 10 = 30s

Explanation :-

${ \bigstar{ \underline{According \: to \: the \: question, }}}$

$\implies\sf \: F = \frac{m(v-u)}{t} \\ </p><p> \implies\sf \: F = \frac{0.3(75-0)}{0.01} \\ </p><p> \implies \sf \: F = \frac{0.3 \times 75 \times 100}{1} \\ </p><p> \implies{ \red{ \boxed{\sf {F = 2250 N}}}}$

$\therefore\sf{ \underline {\: Force \: exerted \: by \: Nail = 2250N}}$

Change in momentum :-

$\implies\sf \: P= Mv$

$\implies\sf \: P = 0.3 \times(75-0)$

$\implies\sf \: P= 22.5$

Answer 2

Answer:

Explanation:this may help you

All the best