Question

2.
A high speed train travels at a speed of 200 km/h
If the train sets off from Station at 12 24 and
reaches Station B at 14.12, find the distance
between the two stations, giving your answer in
metres​

Answer 1

(This attachment is to find the total time taken by the train to complete the journey)

Answer:

Distance travelled by the train is 360 km or 360000 meters .

Step by step explanation:

▪︎Given:

Speed of the train = 200 km/hr

Till 12:24 p.m the train starts the journey and ends at 14:12 p.m .

▪︎To find:

The distance traveled by the train in meters

▪︎Taken:

Distance:

$\boxed{D=S×T}$

Where,

D = Distance

S = Speed

T = Time

▪︎Concept:

To find the distance travelled first find the total time the train taken to complete the journey.

So , total time taken to complete the journey is :

=> 1 hour and 48 minutes

(You can see in the attachment)

▪︎Solution:

$Taken,D=S×T$

$\mapsto{D=200km/hr×(1hr×\frac{48min}{60min})}$

$\mapsto{D=200km/hr×(1hr×\frac{4}{5})}$

(Now,make mixed fraction into improper fraction)

$\mapsto{D=200km/hr×\frac{9}{5}}$

$\mapsto{D=40×9}$

$\mapsto{D=360km}$

So , now find the distance travelled by train in meters by multiplying it with 1000 .

(Because 1 km = 1000 m)

Distance in meters:

$\Rightarrow{360km×1000}$

$\Rightarrow{360000\:meters}$

▪︎Extra information:

To find Speed :

$S=\frac{D}{T}$

To find Time :

$T=\frac{D}{T}$

To find Velocity :

$V=\frac{Dp}{T}$

Where,

V = Velocity

Dp = Displacement

T = Time

To find Acceleration :

$A=\frac{V1-V}{T}$

Where,

A = Acceleration

V1 = Final velocity

V = Initial velocity

T = Time

Answer 2

Step-by-step explanation:

GIVEN:

SPEED OF TRAIN = 200 KM/H

TOTAL TIME TAKEN TO REACH FROM STATION A TO STATION B= 14:12-12:24=1:48 =1 HR 48 MINS.

TO FIND:

DISTANCE TRAVELLED BY THE TRAIN.

ALGORITHM TO SOLVE THIS PROBLEM:

STEP 1.CONVERT TOTAL TIME TAKEN TO REACH STATION B TO HOURS.

STEP 2. USING FORMULA:

D=S×T , FIND THE DISTANCE.

STEP 3.FROM STEP 2 DISTANCE WILL COME IN KM COVERT IT TO METRE BY MULTIPLYING 1000 TO IT.

SOLUTION:

COVERTING 1 HR 48 MIN TO HR

1 +48/60 HR=1 +4/5 HR=9/5 HR.

SPEED = 200 KM/H

D=S×T=200×9/5=360 KM.

NOW 1 KM=1000 M

360 KM= 360×1000=360000 M.

HENCE DISTANCE IN METRE IS 360000 M.