Question

2 A is passing through a conductor of resistance 200 Ω for 5 mts .Calculated the heat energy produced
(2)

Answer 1

Answer:

800 joule heat energy

Explanation:

the Joule's equation : H = I^2RT

Here we have ;

R = 200 OHM. , I = 2 A ,

• note : - [ Current is the rate of flow of charge; it is the amount of charge flowing per second through a conductor. So a current of 1 amp is 1 coulomb of charge flowing past a point every second. Likewise a coulomb is the same as an ampere-second! ]

HEAT ENERGY = I^2RT

• H = (2)^2 × 200 × 1

( T = 1 sec from note )

H = 4 × 200

H = 800 J.

Answer is 800 joule . heat energy

Answer 2

Given:

Current I = 2A

Resistance R= 200 Q

Time t = 5

The heat developed in any electric device for a given time is given by Joule's law of heating,

H = 1² Rt

H=(2)²x 200 × 5 = 4000 J

So,the heat developed in the conductor is4000 J