Question

2.
A juggler is throwing balls in vertically upward direction at an regular interval of 1 sec. Such that 3
balls are always in air. Find out the initial velocity of each ball
(4) 10 m/s
(3) 15 m/s
(2) 20 m/s
(1) 30 m/s​

Answer 1

Given

• A juggler throws balls vertically upward
• Time = 1 sec
• He throws balls at a speed such that there are 3 balls always in air

To Find

• Initial Velocity of each ball

Solution

● v = u + gt

● So here the time would be 3 seconds and the ball thrown first would reach the maximum height then the time would be 3/2, which is 1.5 sec

✭ Initial Velocity of the balls :

→ v = u + gt

• v = 0 m/s
• u = ?
• g = -10 m/s²
• t = 1.5 sec

→ 0 = u + (-10) × 1.5

→ -u = -15

→ Initial Velocity = 15 m/s

∴ The initial Velocity of the balls is 15 m/s, i.e Option b

Answer 2

Answer:

Given :-

• Regular interval of throwing ball = 1 sec
• Total ball = 3

To Find :-

Initial velocity of each ball

Solution :-

$\boxed { \sf firstly \: let s \: see \: the \: concept}$

Here is a juggler who is throwing 3 ball upward in time interval of 1 sec and we have to find initial velocity.

By adding time of three ball = 1+1+1 = 3 sec and when divided by 2 = 1.5 sec.

Let's solve

As we know that

v = u + gt

Here,

V = Final Velocity = 0 m/s

U = Initial velocity = ?

G = Gravity = -10 m/s

T = Time = 1.5 sec

$\sf \: 0 = u + -10 \times 1.5$

$\sf \: 0 = u + - 15$

$\sf - u = - 15$

$\sf \cancel - u = \cancel - 15$

Hence :-

When the juggler throws a ball then the velocity of ball is 15 m/s.