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A leap of 1m can be taken inls. After every 5 leaps taken in the forward direction, 3 leaps in the
backward direction will be taken. In a journey of 13 m of displacement
a) Average velocity is 2.5 ms
b) Total time taken is 23 s
c) Total displacement required is 6 m
d) Total time taken is 37 s
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Answer:
Time taken to move first 5 m forward = 5 s .
Time taken to move 3 m backward = 3 s.
Net distance covered = 5-3=2 m.
Net time taken to cover 2 m = 8 s.
Drunkard covers 2 m in 8 s .
Drunkard covered 4 m in 16 s .
Drunkard covered 6 m in 24 s.
Drunkard covered 8 m in 32 s.
In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.
Net time taken by the drunkard to cover 13 m= 32+5 37 s.
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