Question

2. A longitudinal pulse is produced in a slinky. The frequency of the pulse is 60 Hz and it travels at a speed of 3 cm/s. the separation between consecutive compressions is : (A) 90 cm (B) 0.5 cm (C) 2 cm (D) 1.25 cm​

Answer 1

$No \: \: option \: \: is \: \: correct. \\ The \: \: answer \: \: is \: \: right: 0.05 \: cm$

Explanation:

$Given, \: \: \upsilon = 3 \: cm {s}^{ - 1} \: \: \: and \: \: \: \nu = 60Hz \\ we \: \: know \: \: \boxed{ \upsilon = \lambda \times \nu} \\ Now, \: \: \: putting \: \: values \\ 3 \: cm {s}^{ - 1} = \lambda \times 60Hz \\ \lambda = \frac{3 \: cm {s}^{ - 1} }{60Hz} \\ \: \: \: \: \: = \boxed{ 0.05 \: cm} \\ So, \: \: the \: \: separation \: \: between\\ consecutive \: \: compressions \: \: is \: \: 0.05 \: cm.$