Question

2. A machine depreciates
every year at the rate of 20% of
its value at the beginning of the
year. The machine was
purchased for Rs 500000 when
new. Find its price after 3 years​

Answer 1

Answer:

cost of New machine =500000

rate of depreciates =20%

price After 3 years =?

Step-by-step explanation:

si= p*t*r/100

si=500000*3*20/100

si= 300000

Answer 2

${\fcolorbox{pink}{white}{answer}}$

$\boxed{\red❥GIVEN:-}$

$P = 500000, r = 20\%,  n = 3yrs$

$A = P[( \frac{1 - r}{100 } {)}^{n}]$

$A = 500000[( \frac{1 - 20}{100 } {)}^{3}]$

$A = 500000 \times ( \frac{4}{5} {)}^{3}$

$A = 500000 \times( ( \frac{4}{5} ) \times (\frac{4}{5}) \times (\frac{4}{5} ))$

$A =256000$

$\small{The \: value \: of \: machine \: after 3 years \: is \boxed{ Rs. 2916.}}$