Question

2) A machine displaces a load of 150 kgf when MA of 6 is applied to it. Find

the effort?​

Answer 1

Answer:

Length of  = 2m

length of  = 0.1M

length  = length of -length of

=2−0.1=1.9m

so, velocity ratio = length of effort arm/length of load arm = 1.9/0.1 = 19

use formula, velocity ratio = load/effort

19 = 100kgf/effort

effort = 100/19= 5.26 kgf

hence,5.26 effort is required.