2. A man has to go 100m north, 80m due East and 40m due South to reach a field. What is the distance and displacement.
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Explanation:
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BrainlyHelper
BrainlyHelper
25.05.2018
Physics
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A man has to go 50m due north , 40m due east and 20m due south to reach a field . A) what distance he has to walk to reah field? B) What is his displacement from his house to the field ? Concept of Physics - 1 , HC VERMA , Chapter "Rest and Motion : Kinematics
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prmkulk1978
prmkulk1978 Ace
Solution:
Distance :
Distance is the total path covered by the man.
Distance travelled by man=50m+40m+20m=110m
Displacement :
Displacement is the shortest path between source [house] and destination [ field]= AB
See the figure :
Draw Perpendicular BE to AC.
BE=CD=40m
AE=AC-CE=50-20=30
NOW, DISPLACEMENT AB=√AE²+EB²
AB=√30²+40²=50m
Angle with horizontal is given by tanθ=30/40=3/4
θ=tan⁻¹[3/4] direction north to east.
∴His displacement from his house to field is 50m , tan⁻¹[3/4] direction north to east.
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Answer:
Explanation:
Distance :
Distance is the total path covered by the man.
Distance travelled by man=50m+40m+20m=110m
Displacement :
Displacement is the shortest path between source [house] and destination [ field]= AB
See the figure :
Draw Perpendicular BE to AC.
BE=CD=40m
AE=AC-CE=50-20=30
NOW, DISPLACEMENT AB=√AE²+EB²
AB=√30²+40²=50m
Angle with horizontal is given by tanθ=30/40=3/4
θ=tan⁻¹[3/4] direction north to east.
∴His displacement from his house to field is 50m , tan⁻¹[3/4] direction north to east.
Explanation:
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