Question

2
A man sold two properties of Rs 25 lac each one
at 10% loss, other at 10% profit. What is net profit
loss?​

Answer 1

Step-by-step explanation:

Given:

• Cost price of both properties is 25 lakh i.e Rs 2500000
• He sold one property at 10 % loss and another at 10% profit.

To Find:

• His net profit or loss on whole transaction.

Solution: Total cost of both properties=

• 25 Lakh + 25 Lakh = 50 lakh i.e Rs 5000000

† At first property he made a loss of 10%†

∴ 10% of Cost Price of first property

$\small\implies{\sf }$ 10/100 x 2500000

$\small\implies{\sf }$ 10 x 25000 = Rs 250000 ( Total loss )

→ S.P = C.P – Loss

→ S.P = 2500000–250000

→ S.P = Rs 2250000 ( Of first property)

† At second property he made a profit of 10% †

∴ 10% of Cost Price of second Property

$\small\implies{\sf }$ 10/100 x 2500000

$\small\implies{\sf }$ 10 x 25000 = Rs 250000 ( Total profit )

→ S.P = C.P+ Profit

→ S.P = 2500000+250000

→ S.P = Rs 2750000 ( Of second property)

Therefore, Total S.P of both properties =

• 2250000+2750000=Rs 5000000

Here, Total C.P of both properties= Total S.P of both properties so man doesn't make any Profit of loss on whole transaction.