Question

2.
A man standing on a platform pulls a mass of
50 kg as shown below. If the string and pulley are
light and frictionless and string can bear a
maximum load of 750 N then maximum possible
acceleration of the block
ma
F
F = 75
5.
50 kg
(1) 10 ms-2
(2) 15 ms-2
(3) 20 ms-2
(4) 30 ms-2
in the figure iron bolova uch of the cables at​

Answer 1

Answer:

Correct option is

B

250N

The force with which the man pulls the rope=Tension in the rope=T

Thus the tension in the string attached to the platform=2T

Normal reaction acts on the man upwards and the platform downwards.

Considering forces acting on the platform,

Mg+N=2T

Considering forces acting on the man,

mg=N+T

⟹(M+m)g=3T

⟹T=250N

Answer 2

Given: A man standing on a platform pulls a mass of 50 kg. The string and pulley are light and frictionless and the string can bear a maximum load of 750 N.

To find: The maximum possible acceleration of the block.

Solution:

• The load acts as a force on the pulley.
• Force applied on an object is because that changes or tends to change its state of motion or rest.

        $F = m * a$

• Here, F is the force on the pulley, that is the load on the pulley, m is the mass of the load, that is the block and a is the maximum possible acceleration.

        $750 N = 50 kg * a$

        $a = 15 ms^{-2}$

Therefore, the maximum possible acceleration of the block is 15 ms⁻².