Question

2. A massless string of length L passes over a frictionless pulley whose axis is horizontal. Two monkeys hang from the ends of the string at the same distance L/2 from the pulley, the monkeys start climbing upward simultaneously. First monkey climbs with a speed v relative to the string and the second with a speed 2v. Both monkeys have equal masses. Then the time taken by the first and second monkey is meeting each other are respectively ​

Answer 1

As the pulley is frictionless and masses of monkeys are equal so it takes same amount of time for both monkeys to reach the pulley.

Total relative velocity is vt=v+2v=3v

Total distance covered ,S=l/2+l/2=l

The time taken by each monkey is, t=vtS=3vl