Question

2. A meter rod pivoted at its one end is
rotated through 120°. Then displacement
of its free end will be
20
(b) 3 m
(c) √2m
(d) V3 m
(a) 2m​

Answer 1

Answer:

It is 2sin60°=2(√3/2)=√3=1.732m.Ans..

Explanation:

displacement/ sin 120= one meter/sin 30

displacement/.87= 1/.5

.5 displacement = .87

displacement= 1.74 meters = √3

Answer 2

Answer:

(d) √3m

1.732 m

Explanation:

• Here we have a triangle of 120 degrees at the centre of the rotation and into it there is two 30 degree angles at the perimeter.
• If the displacement is the straight line difference between where the rod's tip began and terminated.

The Law of Sines can be applied in this situation.

one meter/sin 30= displacement/sin 120= displacement/sin 120= displacement/sin 120= displacement/sin 120

1/.5= displacement/.87

a displacement of.5 = a displacement of.87

1.74 metre = displacement

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