Question

2
A mild steel material having a cross-sectional
area of 10 cm and a mean circumference of
40 cm has a coil of 180 tums wound around it.
Find Ampere-turns and current required to
produce a flux of 800 uWb in the ring.
[ Assume 4 = 380)​

Answer 1

Answer:

Magnetic field strength (or magnetizing force), H = NI=l ampere per metre, where l is the mean length of the flux path in metres. Thus mmf = NI = Hl amperes.

Explanation:

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