Question

2. A milk-can holds 21.70 litres of milk. How many such milk-cans will
be required to hold 672.70 litres of milk?

please answer by process i will mark you brainist

answer should be 2.31 I only need process​

Answer 1

Answer:

31

Step-by-step explanation:

Given,

Milk contained by 1 can = 21.70 litres

To find,

Cans required to carry 672.70 litres

Solution,

Cans required to carry 672.70 litres milk

= Total milk to be carried / Milk in one can

= 672.70 /21.70

= 31

Answer 2

$no \: of \: can \: = \frac{total \: quantity \: of \: milk \: }{milk \: in \: one \: can} = \frac{672.70}{21.70} = 31 \: cans$

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