2. A monkey climbs a greasy pole 12 metres high. He ascends 3 metres
in first minute and slips down 1 metre in the alternate minute. In
which minute he reaches the top ?
Answers
Answered by
2
Answer:
In 1 minute the monkey climbs 12 metres but then he takes 1 minute to slip down 5
metres. So, at the end of 2 minutes the net ascending of the monkey is 12 – 5 = 7 metres.
So, to cover 63 metres the above
process is repeated
63
= 9
7
times. Obviously, in 9 such happenings the monkey will slip 8 times, because on 9th time, it
will climb to the top. Thus, in climbing 8 times and slipping 8 times, he covers 8 × 7 = 56 metres.
Time taken to cover 56 metres
=
56 × 2
= 16 minutes
7
Remaining distance
= 63 – 56 = 7 metres
Time taken to ascend 7 metres
=
7
minutes
12
∴ Total time taken = 16 +
7
12
= 16
7
minutes.
12
Answered by
1
Answer:
2.50 is correct answer
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