Math, asked by rkanya2007, 10 months ago

2. A mother and her two daughters got a room constructed for 63,000. The
elder daughter contribute 3/8 of her mother's contribution while the younger
daughter contributes 1/2 of her mother's share. How much do the three
contribute individually?​

Answers

Answered by suryasekhar
2

Answer:

mother=x

x+3x/8+x/2=63000

8x+3x+4x=63000×8

15x=504000

x=33600

then elder daughter is= 33600×3/8=4200×3=12600

younger one is = 33600/2=16800

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Answered by mayanksinghsayala
2

Answer:

mother contribution= 33600

elder mother contribution=12600

younger daughter contribution=16800

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