2. A mother and her two daughters got a room constructed for 63,000. The
elder daughter contribute 3/8 of her mother's contribution while the younger
daughter contributes 1/2 of her mother's share. How much do the three
contribute individually?
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Answered by
2
Answer:
mother=x
x+3x/8+x/2=63000
8x+3x+4x=63000×8
15x=504000
x=33600
then elder daughter is= 33600×3/8=4200×3=12600
younger one is = 33600/2=16800
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Answered by
2
Answer:
mother contribution= 33600
elder mother contribution=12600
younger daughter contribution=16800
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