Question

2. A number is first increased by 10% and then reduced by 10%. The number
(a) does not change (b) decreases by 1% (c) increases by 1% (d) none of thes
​

Answer 1

Answer:

Step-by-step explanation:

let 1st no. be x

increase by 10%  

x+x/10=11x/10

now decrease 10%  

11x/10-(11x/10)/10=99x/100

the decrease is x-99x/100

x/100

decrease % is 1%

Ans : b(decrease by 1%)

Answer 2

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Decreases by 1%✔

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Given Problem:

A number is first increased by 10% and then reduced by 10%. The number

(a) does not change (b) decreases by 1% (c) increases by 1% (d) none of these.

Solution:

Let the required number be 100.

Then, according to the question,

⇒ Firstly, the number is increased by 10 %

⇒ 100 + (100*10)/100

⇒ 100 + 10

= 110

Secondly, it is decreased by 10 % 

⇒ 110 - (110*10)/100

⇒ 110 - 11

⇒ 99

Net increase or decrease percentage

= (Original Number - New Number)*100/100

⇒ (100 - 99)*100/100

⇒ (1*100)/100

⇒ 100/100

= 1 %