Math, asked by krishnakrishna77334, 5 months ago

2.
A nursery school playground is 160 m long and 80 m wide. In it 80 mx 80 m
is kept for swings and in the remaining portion, there is 1.5 m wide path
parallel to its width and parallel to its remaining length as shown in below
figure. The remaining area is hicovered by grass. Find the area covered by
grass.
1.5 m
1.5 m
80 m
Swings
80 m
-80 m​

Answers

Answered by techmanoj777
11

Step-by-step explanation:

Area of school playground is 160 m × 80 m = 12800 m2 Area kept for swings = 80 m × 80 m = 6400 m2 Area of path parallel to the width of playground = 80 m × 1.5 m = 120 m2 Area of path parallel to the remaining length of playground = 80 m × 1.5 m = 120 m2. Area common to both paths = 1.5 m × 1.5 m = 2.25 m2. [since it is taken twice for measuerment it is to be subtracted from the area of paths] Total area covered by both the paths = (120 + 120 – 2.25) m2 = 237.75 m2. Area covered by grass = Area of school playground – (Area kept for swings + Area covered by paths) = 12800 m2 – [ 6400 + 237.75] m2 = (12800 – 6637.75) m2 = 6162.25 m2

Answered by Aria07
3

Answer:

answer is above...........

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