Question

2. A nut is opened by a wrench of length 10 cm. If the
least force required is 5.0 N, find the moment of force
needed to turn the nut.
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Answer 1

Answer:

Distance=10cm=0.1m

force=5N

moment of force=distance×force=0.1×5=0.5Nm

Hope it helps!!!

Answer 2

Answer:

Moment of force needed to turn the nut is 0.5 N-m

Explanation:

Given,

A nut is opened by a wrench of length 10 cm. = 0.1 m

The least force required is 5.0 N

To find: The moment of force needed to turn the nut.

Solution:

Moment of force is given as:

Moment of force = perpendicular distance * Force

or, M_f = r * F

here, r = 0.1 m and F = 5.0 N

Substituting the values,

M_f = 0.1 * 5

M_f = 0.5 N-m

Therefore, Moment of force needed to turn the nut is 0.5 N-m.