2)A parallelogram has sides 30 m and 40 m and one of its diagonals is 20m
long. Find the area of the parallelogram.
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Answer:
let WXYZ be the given parallelogram
area of parallelogram WXYZ = 2 x (area of triangle WXY)
now w= 30m, x= 20m and y= 40m
s=1/2 x (30+20+40) = 45
Area of triangle ABC = √s(s-w)(s-x)(s-z)
= √45(45-30)(45-20)(45-40)
=√45×15×25×5
=290
area of parallelogram ABCD = 2 x290 = 580sq m
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