2. A parallelogram has so
15 cm, find the distance between the shorter sides.
3. The diagonals of a rhombus are 30 cm and 16 cm. Find its area, the length of a side and
its perimeter
4. Each side of a rhombus is 61 cm and one of its diagonals is 22 cm long. Find (i) the length
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2.
Answer:
9 cm
Step-by-step explanation:
The area of a parallelogram, A = length of parallel sides* distance between them. So area =15*6 = 90 sq cm, So distance between the shorter sides will be 90/10 = 9 cm.
3. Answer
Step- by-step explanation:
Area = 1/2 × product of diagonals
so area = 1/2 × 30 ×16 = 240 cm²
also diagonals bisect each other at right angles
so 1/2×30= 15cm,,,, 1/2×16 =8cm
therefore by Pythagoras theorem,
15² + 8² = side²
√289 = side
side = 17 cm
thus perimeter = 4 × 17 = 68 cm
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