Question

2 A particle has a displacement of 40 m along OX in the first 5 s and 30 m perpendicular to next Ss. The magnitude of the average velocity of the particle during the time interval of 10 a) 6 ms ! b) 7 ms d) 5 ms c) 8 ms e time and​

Answer 1

Answer:

5m/s

Explanation:

displacement=√40² + 30²=√2500 =50

time 5+5 =10sec

velocity=displacement/time =50/10 =5m/s