Question

2. A particle is dropped from a height of 50 m. If the
particle loses its 20% mechanical energy during
the impact with the ground, upto what height will
it rebound after the second impact?
(1) 40 m
(2) 36 m
3) 32 m
(4) 28 m​

Answer 1

Answer:

apply conservation of energy in this question

Explanation:

initial energy=m×g×h

=500m

particle loses its 20% mechanical energy so remaining energy is 80% of the initial.

final energy =80% of 500m

=400m

apply conservation of energy again to get

400m = mgh

h=40 meters

option(1) is correct