Question

,
2. A particle moves 3m North 4m east and finally 6m South. Calculate the
distance and displacement.​

Answer 1

Answer:

5m displacement and 13 m distant

Explanation:

when a particle move in north ,east and south

to find distance we add 3m,4m and 6m then we find distance

to find displacement

we make a figure to respect direction

then our figure make like a right triangle on rectangle then use Pythagoras theorm we find displace ment

Answer 2

Let north, south east be represented by N, S, E.

According to question:

⇒ 3m in North = 3N,  then

⇒ 4m in East(right) = 3N + 4E , then

⇒ 6m in South = 3N + 4E + 6S

Total displacement = 3N + 4E + 6S

But as we know, north is opposite to south, N = - S.

∴ displacement = 3(-S) + 4E + 6S = 4E + 3S  

As south and east are at right angle to each other, we can't them directly.

Using Pythagoras theorem,

Displacement = √3² + 4² = 5

Displacement is 5 m

But in terms of distance, we can add it directly as it doesn't depend on direction, distance = 3 + 4 + 6 = 13 m