Physics, asked by shubham2920, 1 year ago

2. A particle moves along the sides AB, BC, CD of a square
of side 25 m with a velocity of 15 ms. Its average velocity
(a) 15 ms-
(c) 7.5 ms -1
(b) 10 ms
d) 5 ms​

Answers

Answered by mohit2270
6

Answer:

As

Average Velocity = variable velocity

Total velocity

AB, BC CD sides equal

Explanation:

Averg. velocity= 25+25+25 ms'

15

= 75/15= 5ms'

ANSWER- (d).

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