Question

2. A particle of mass 10 g is performing a simple oscillation along a straight line.
If its oscillation period is 2 s and spread is 10 cm then (i) 2 cm from equilibrium
Determine its kinetic energy at a distance and (ii) kinetic energy 5 cm away from equilibrium
Do.​

Answer 1

Kinetic energy K=

2

1

mω

2

(a

2

−y

2

)

=

2

1

×10×(

2

2π

)

2

[10

2

−5

2

]=375π

2

erg

Answer 2

Answer:

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