Question

2.
A particle starting from rest, moves in a circle of
radius P. It attains a velocity of V, m/s in the nth
round. Its angular acceleration will be
[NEET-2019 (Odisha)]
v²
(1) -rad/s2
4πηr
(2)
V
(3) -rad/s2
v²
2nnr
2
(4) -rad/s2
4πηr2
Vorad/s2
n​

Answer 1

Answer:

A particle moves in a circle of  radius r. It attains a velocity of V, m/s, Its angular acceleration will be $a=rw^{2}$

Explanation:

• The angular acceleration is the change of angular velocity of a rotating body with time

• The relation connecting linear velocity(v) and angular velocity(w) is $v=rw$

• The force acting on a body to keep it in a circular orbit is known as centripetal force

• If a mass (m) moving with velocity (v) in a circular path of radius (r) the centripetal force is $F=mv^{2}/r$

• From Newton's second law the force is $F=ma$

by equating the forces

⇒

$ma=mv^{2} /r\\a=v^{2}/r$

put the value of v

⇒$a=\frac{(rw)^{2} }{r} =rw^{2}$