2. A particle starts from the origin, goes along the X-axis
to the point (20 m, 0) and then returns along the same
line to the point -20 m, 0). Find the distance and
displacement of the particle during the trip
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Distance: Actual path length travelled front initial to final point.
Displacement: Shortest path between initial and final point.
Solution:
lets first draw the path of object.
- object moves from O to A then return to O and goes to final point B
- OA = 20m , OB = 20m
- During the motion:
Distance
- OA + AO + OB
- 20 + 20 + 20 = 60m
Displacement
- shortest path between initial and final points
- initial point = 0 , final point = B
- OB = 20m (in negative x-axis)
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Explanation:
Distance: Actual path length travelled front initial to final point.
Displacement: Shortest path between initial and final point.
Solution:
lets first draw the path of object.
object moves from O to A then return to O and goes to final point B
OA = 20m , OB = 20m
During the motion:
Distance
OA + AO + OB
20 + 20 + 20 = 60m
Displacement
shortest path between initial and final points
initial point = 0 , final point = B
OB = 20m (in negative x-axis)
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