2.
A passenger takes 2 minutes standing on a
moving escalator to reach the top. If escalator is
stationary he takes 3 minutes to walk up. Time
taken to reach the top when he walk up on moving
escalator
(1) 2.4 minutes (2) 5 minutes
(3) 1 minute
(4) 1.2 minutes
Answers
Answer: 1.2 minutes
Explanation:
Let the distance traveled in both the cases be “d”.
Case 1: when the passenger is standing on a moving escalator
Time take = 2 minutes
So, the velocity of escalator w.r.t the ground = d/t = d/2 ….. (i)
Case 2: when the passenger is walking on a stationary escalator
Time taken = 3 minutes
So, the velocity of the passenger w.r.t the escalator = d/3 …… (ii)
Case 3: when the passenger is walking on a moving escalator
Let the time taken by the passenger to reach the top when he is walking upon the moving escalator be “t”.
Here,
The velocity of passenger w.r.t the ground, “d/t”
= [velocity of escalator w.r.t the ground] + [the velocity of the passenger w.r.t the escalator]
Substituting the values from (i) & (ii)
= d/2 + d/3
= d[(2+3)/6]
= 5d/6
∴ d/t = 5d/6
⇒ t = 6/5 = 1.2 minutes
Thus, the passenger takes 1.2 minutes to reach the top by walking upon the moving escalator.
Answer:
1.2 is ans
Explanation:
VGE =Vg-Ve
y/Tge=y/Tg-y/Te
1/T =1/3+1/2
hence
T =6/5
=1.2