2. A patient in a hospital is given soup daily in a cylindrical bowl of
diameter 7 cm. If the bowl is filled with soup to a height of 4 cm, how
much soup the hospital has to prepare daily to serve 250 patients?
Answers
Answer:
Hey Buddy!!!
Diameter = 7 cm
Radius , r = 7 / 2 cm
Height , h = 4 cm
Quantity of soup in 1 bowl = Volume of one cylindrical bowl
= πr²h
= 22 / 7 × [7 / 2] ² × 4
= 154 cm³
Quantity of soup prepared in 250 bowls = 250 × 154
= 38500 cm³
= 38.5 litres [ 1 cm³ = 0.001 litres]
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Tc!!
Answer:
38.5 L
Step-by-step explanation:
h = 4 cm ; r = d/2 = 7/2 cm
hence the volume of the soup for 1 patient is = πr²h
= (22/7)×(7/2)×(7/2)×4 cm³
= (22/2)×(7/2)×4 cm³
= (22×7) cm³
= 154 cm³
for 250 patient total volume of soup is = (154×250) cm³
= 38500 cc
= 38.5 L ∵1000 cc = 1 L