2. A pendulum exhibit 2400 oscillations in 10 minutes. Find a) frequency b)time period
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Answer:
Given
Number of Oscillations, N=40
Time t=1min
Frequency f=
t
N
=
60
40
=0.667Hz
Time period,T=
f
1
=1.5sec
Hence, frequency is 0.667Hz and time period is 1.5sec
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