Question

2.
A person moves towards north with uniform
speed of 15 m/s and cover 16 m. After this he
moves towards east and covers 6 m and finally
covers 8 m distance with same speed in south.
Find out
(i) Distance travelled by person
(ii) Displacement of person
(iii)Average velocity of person​

Answer 1

Answer:

a.30 m

b.10 m

c.5 m/s

Step-by-step explanation:

We are given that

AC=16 m

CD=6 m

DE=8 m

We have to find

a.Distance covered by traveled by person=Total path length

Therefore, distance covered by person=16+6+8=30 m

b.Displacement covered by person=Distance between final position and initial position

We have to find AE

BCDE is a rectangle

BC=DE=8 m

CD=BE=6 m

AB=AC-BC=6-8=8 m

AE=$\sqrt{AB^2+BE^2}$

AE=$\sqrt{8^2+6^2}$

AE=$\sqrt{100}$

AE=10 m

Hence, the displacement of a person =10 m.

c.We have to find the average velocity

We have uniform  uniform =15 m/s

Then, time=$\frac{Distance}{speed}$

Time=$\frac{30}{15}=2 sec$

Average velocity=$\frac{Displacement}{time}$

Average velocity=$\frac{10}{2}=5m/s$

Hence , the average velocity=5 m/s